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a cube has a volume of 1728 cu mm. If the allowable error in the edge of a cube is 0.04 mm,compute the allowable error in the volume of the cube?

Guest Mar 5, 2017
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The edge of a cube with a volume  of 1728mm^3   =   12mm

 

So....the allowable error, E, would be

 

(12 - .04)^3 < E < (12 +  .04)^3

 

1710.77mm^3 < E < 1745.34mm^3

 

 

cool cool cool

CPhill  Mar 5, 2017

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