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mike withdrawed money from the bank he spent a fourth of it on gas and has $90 left. how much money did he withdraw?

 Jun 16, 2017
 #1
avatar+9460 
+3

Let's call the amount of money he withdrawed   " m " .

 

m - ( \(\frac14\) )m  =  90            Factor out an  m  on the left side.

 

m( 1 - \(\frac14\) )   =  90

 

m(\(\frac44-\frac14\))  =  90

 

m(\(\frac34\))  =  90                     Multiply both sides of the equation by \(\frac43\)

 

m  =  90 * \(\frac43\)

 

m  =  120

 Jun 16, 2017
 #2
avatar+118587 
+2

If he spent  a    1/4   then he must have 3/4   left

So   $90   is   3/4     of the original amount

 

If you divide that by 3 you will have 1/4 of the original amount so

90 / 3   =  $30

$30 is   1/4   of the original amount.  

If you multiply that by 4 you will have the orriginal amount.

 

$30 * 4 =   $120

 Jun 16, 2017
 #3
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+1

360 NO SCOPE!

 Jun 19, 2017

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