if sin x^0=7/9,find x

 

sin x^0=7/9,find x

x^0=1    

(sinx)^0=1

so the x is irrelvant

 

OH I get you - that is not a power of 0 that is a degree sign - silly me.  It would have been better just to write degrees :))

$$\\sin x^0=7/9\\
asin(7/9)=x\\$$

 

arc sin is the same as inverse sin

If you need to find an angle then you need to use inverse (or arc) trig    :)

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{7}}}{{\mathtt{9}}}}\right)} = {\mathtt{51.057\: \!558\: \!731\: \!019^{\circ}}}$$