If the base of a triangle is shortened by 60 percent, by what percent must the height be increased if the area is to remain the same?

A = bh/2

So...if the base is shortened by 60%, it's only 40% of what it used to be...so.......

.40bx/2   = bh/2      where x is what we're looking for.....

.40bx =  bh

.40x = 1 h

x = 1 h/.40

x = 2.5h     .......so the height must be increased by 2.5 times