If you could please help me out with this that would be awesome!
Also, I would like to thank CPhill for being such an amazing person. You helped me out so much today with my math problems. Thank you!
There are several answers possible ......
Using the form y = A sin ( Bx + C) + D
The period of the graph is 15 units in length.....then each quarter point = 15/4 units
The amplitude of the graph = A = 4
The midline of the graph is y = 1 = D
We can solve for B thusly
pi/2 = (15/4)B
pi/ 2 * (4/15) = B
(2/15)pi = B
And we can find C thusly......note that we are shifting the normal cosine curve to the right
1 = sin [ (2/15)pi (15/4) - C] + 1 subtract 1 from both sides
0 = sin [ ( pi/2) - C ] → cC = pi /2
So....our function is
y = 4 sin [ (2/15)pi* x - pi/2 ] + 1
Here's the graph : https://www.desmos.com/calculator/gdqmefwhyc