If you have 6x(8x+6)+9(4x+3), how would you finish factorising this?
Cananyone help?
+128407 6x(8x+6)+9(4x+3) = factor a 2 out of the terms in the first parentheses
(6x)(2)(4x + 3) + 9(4x + 3)
12x ( 4x + 3) + 9 (4x + 3) = ....(4x + 3) is the common factor.....
(12x + 9) (4x + 3) = factor a 3 out of the terms in the first parentheses
3(4x + 3) (4x + 3) =
3 (4x + 3)^2
+128407 6x(8x+6)+9(4x+3) = factor a 2 out of the terms in the first parentheses
(6x)(2)(4x + 3) + 9(4x + 3)
12x ( 4x + 3) + 9 (4x + 3) = ....(4x + 3) is the common factor.....
(12x + 9) (4x + 3) = factor a 3 out of the terms in the first parentheses
3(4x + 3) (4x + 3) =
3 (4x + 3)^2
