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If you have 6x(8x+6)+9(4x+3), how would you finish factorising this?

 

Cananyone help?

Guest Mar 11, 2015

Best Answer 

 #1
avatar+80875 
+5

6x(8x+6)+9(4x+3)  =      factor a 2 out of the terms in the first parentheses

(6x)(2)(4x + 3) + 9(4x + 3)

12x ( 4x + 3) + 9 (4x + 3) =  ....(4x + 3)  is the common factor.....

(12x + 9) (4x + 3)  =    factor a 3 out of the terms in the first parentheses

3(4x + 3) (4x + 3) =

3 (4x + 3)^2

 

  

CPhill  Mar 11, 2015
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1+0 Answers

 #1
avatar+80875 
+5
Best Answer

6x(8x+6)+9(4x+3)  =      factor a 2 out of the terms in the first parentheses

(6x)(2)(4x + 3) + 9(4x + 3)

12x ( 4x + 3) + 9 (4x + 3) =  ....(4x + 3)  is the common factor.....

(12x + 9) (4x + 3)  =    factor a 3 out of the terms in the first parentheses

3(4x + 3) (4x + 3) =

3 (4x + 3)^2

 

  

CPhill  Mar 11, 2015

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