In △ABC, AB=6 cm, AC=15 cm, and m∠A=48°. What is the area of △ABC?

Round only your final answer to the nearest hundredth.

Kakarot_15
May 28, 2017

#1**+2 **

Let's let the base of this triangle be 15 cm, and the height be the skinny purple line.

sin θ = opposite / hypotenuse

sin 48º = height / 6

6 sin 48º = height

area = (1/2)(base)(height)

area = (1/2)(15)(6 sin 48º)

area ≈ 33.44 cm^{2}

hectictar
May 28, 2017