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In right triangle ABC, we have AB = 10, BC = 24, and \(\angle ABC = 90^\circ\).

 

If M is on \(\overline{AC}\) such that \(\overline{BM}\) is an angle bisector of \(\triangle ABC\), then what is \(\cos \angle ABM\) ?

michaelcai  Nov 18, 2017
edited by Melody  Nov 19, 2017

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 #1
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angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

Melody  Nov 19, 2017
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1+0 Answers

 #1
avatar+91241 
+2
Best Answer

angle ABC is a right angle

and  BM bisects ABC then angle ABM is 45 degrees and cos 45 degrees =   1/sqrt2

Melody  Nov 19, 2017

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