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# Inequality

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6*(x-5)-2*(4x+2) ≥ 80, in the numeric set Z (sorry if not right), the result i got was x ≥ -57, it should be write {-57,-58,-59,...} or {...,-59, -58, -57}? And why?

Guest Jul 9, 2017
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#1
+76821
+1

Actually, the solution  is

x ≤ - 57

You can write your solution as

( - ∞ , -57 ]

The bracket shows that the number to its left is included in the solution...infinities are never bracketed but are shown with a parentheses beside them

CPhill  Jul 9, 2017
#2
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thanks, but could you write the process to the result for me? im more confused than a blind man in a shooting.

Guest Jul 9, 2017
#3
+76821
+1

6*(x-5)-2*(4x+2) ≥ 80     simplify

6x - 30 - 8x - 4  ≥ 80      combine like terms on the left

-2x - 34  ≥ 80      add 34 to both sides

-2x  ≥  114

divide both sides by -2......don't forget to reverse the inequality sign as we do in an inequality when we  divide or multiply by a negative  !!!

x ≤ - 57

CPhill  Jul 10, 2017
edited by CPhill  Jul 10, 2017
#4
0

Thank you very much man, you answered my two questions on this site and even explained it, man you helped me a lot, thank you very much, really, thank you.

Guest Jul 10, 2017

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