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is 3i a whole number, a natural number, an integer, or something else?

Guest Aug 19, 2014

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 #2
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$$The imaginary number system is based on $i=\sqrt{-1}$\\
So \\
3i = \sqrt9\times \sqrt{-1} = \sqrt{9*-1} = \sqrt{-9}$$

Melody  Aug 20, 2014
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 #1
avatar+4471 
+5

3i is an imaginary number.

It is the square root of -9.

AzizHusain  Aug 19, 2014
 #2
avatar+91435 
+5
Best Answer

 

$$The imaginary number system is based on $i=\sqrt{-1}$\\
So \\
3i = \sqrt9\times \sqrt{-1} = \sqrt{9*-1} = \sqrt{-9}$$

Melody  Aug 20, 2014

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