+0

is it right?it it is so how do i need to continue from here?

0
305
3
+262

sabi92  Jun 20, 2015

Best Answer

#2
+91412
+15

Sabi has told me that the answer is different from the book answer.

$$\frac{9}{5a^2-11ab+2b^2}+\frac{17}{10a^2+13ab-3b^2}\\\\ =\frac{9}{5a^2-10ab-1ab+2b^2}+\frac{17}{10a^2-2ab+15ab-3b^2}\\\\ =\frac{9}{5a(a-2b)-b(a-2b}+\frac{17}{2a(5a-b)+3b(5a-b)}\\\\ =\frac{9}{(5a-b)(a-2b)}+\frac{17}{(2a+3b)(5a-b)}\\\\ =\frac{9(2a+3b)}{(5a-b)(a-2b)(2a+3b)}+\frac{17(a-2b)}{(2a+3b)(5a-b)(a-2b)}\\\\ =\frac{18a+27b}{(5a-b)(a-2b)(2a+3b)}+\frac{17a-34b}{(2a+3b)(5a-b)(a-2b)}\\\\ =\frac{18a+27b+17a-34b}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{35a-7b}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{7(5a-b)}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{7}{(a-2b)(2a+3b)}\\\\$$

Is it the same now Sabi ?

Melody  Jun 21, 2015
Sort:

3+0 Answers

#1
+91412
+10

Yes, I think it looks good so far, now you just have to get them both with a common denominator.

That will be  (5a-b)(a-2b)(2a+3b)

then you can add the numerators

Melody  Jun 20, 2015
#2
+91412
+15
Best Answer

Sabi has told me that the answer is different from the book answer.

$$\frac{9}{5a^2-11ab+2b^2}+\frac{17}{10a^2+13ab-3b^2}\\\\ =\frac{9}{5a^2-10ab-1ab+2b^2}+\frac{17}{10a^2-2ab+15ab-3b^2}\\\\ =\frac{9}{5a(a-2b)-b(a-2b}+\frac{17}{2a(5a-b)+3b(5a-b)}\\\\ =\frac{9}{(5a-b)(a-2b)}+\frac{17}{(2a+3b)(5a-b)}\\\\ =\frac{9(2a+3b)}{(5a-b)(a-2b)(2a+3b)}+\frac{17(a-2b)}{(2a+3b)(5a-b)(a-2b)}\\\\ =\frac{18a+27b}{(5a-b)(a-2b)(2a+3b)}+\frac{17a-34b}{(2a+3b)(5a-b)(a-2b)}\\\\ =\frac{18a+27b+17a-34b}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{35a-7b}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{7(5a-b)}{(5a-b)(a-2b)(2a+3b)}\\\\ =\frac{7}{(a-2b)(2a+3b)}\\\\$$

Is it the same now Sabi ?

Melody  Jun 21, 2015
#3
+262
+5

yes thank you very much  my answer was wrong because i didnt open the brachets

sabi92  Jun 21, 2015

16 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details