No...the graph of g(x) is continous. The graph of f(x) will look similar to g(x), except there will be a "hole" at x = 4. The reason for this is that "4" makes the denominator of f(x) = 0......and that's not allowed.....
No...the graph of g(x) is continous. The graph of f(x) will look similar to g(x), except there will be a "hole" at x = 4. The reason for this is that "4" makes the denominator of f(x) = 0......and that's not allowed.....
