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If a flat- screen TV is a rectangle with a 53-inches diagonal and a width of 45-inches, What isheight of the screen?

 Feb 17, 2017

Best Answer 

 #1
avatar+36915 
+5

Use Pythagorean theorem

a^ + b^2 = c^2

a^2 + 45^2 = 53^2

a = sqrt(53^2-45^2) = 28 inch height

 Feb 17, 2017
 #1
avatar+36915 
+5
Best Answer

Use Pythagorean theorem

a^ + b^2 = c^2

a^2 + 45^2 = 53^2

a = sqrt(53^2-45^2) = 28 inch height

ElectricPavlov Feb 17, 2017
 #2
avatar+14903 
+5

If a flat- screen TV is a rectangle with a 53-inches diagonal and a width of 45-inches, What isheight of the screen?

 

\(w^2+ h^2=d^2 \)          \( Pythagoras\)

 

\(h=\sqrt{d^2-w^2}=\sqrt{(53^2-45^2)\ inch^2}=\sqrt{784\ inch^2}\)

 

\(h=28\ inch\)

 

\(The \ height \ of \ the \ screen \ is \ 28 \ inch.\)

 

laugh  !

 Feb 17, 2017

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