+0

Just Checking my work.

0
115
1
+123

the indefinite integral form of ((-1+y)/(2 sqrt(y)))^2

is   (-1+y)²         1

∫ ———   dy= — ((y-4) Y+2 log (y))

4y               8

am I correct? I apologize for the deformed nature of my equation. it's difficult for me to type math on my computer.

TheMathGuy  Mar 3, 2017
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#1
+90590
0

Yes that is correct except you forgot the +c

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This is how I would enter it

\int\frac{(-1+y)^2}{4y}\;dy

now open up the LaTex button on the ribbon and paste it in :)

$$\int\frac{(-1+y)^2}{4y}\;dy$$

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this might seem a bit complicated to start with if you do not know any LaTex but this forum is a great place for you to learn.

fractions are easy and very handy, so to write 2/3 as a fraction it is just

\frac{2}{3}

and now I will past this into the  LaTex box

$$\frac{2}{3}$$

Melody  Mar 3, 2017

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