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The planet Mercury orbits the sun in 88 days what its average distance from the sun? Kepler’s Third Law: T 2= P3

Guest Feb 17, 2017
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So  T^2 is PROPRTIONAL to P^3

T^2/R^3 = 4 pi^2 / G M   

    where G = graviational constant    6.67408 x 10^-11 m^3/kg-s^2     M= sun Mass = 1.989 x 10^30kg

 

(88 days x 24 hours x 3600 sec/hr)^2 / P^3 =  2.973949 x 10^-19

P = 5.7927 x 10^10 m

= 57,927,719 km  from Sun

ElectricPavlov  Feb 18, 2017

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