a=6 b=10 and Angle Measure C is 110 degrees, I need to complete the triangle using laws of cosine and sine
+128406 Using the Law of cosines to find "c"......we have
c = sqrt [6^2 + 10^2 - 2(6)(10) cos (110) ] ≈ 13.3
Using the Law of Sines to find angle A, we have
sinA / 6 = sin(110) / 13.3
sinA = 6sin(110)/13.3
arcsin (6sin (110) / 13.3) = A ≈ 25.08°
Angle B = 180 - 110 - 25.08 = 44.92°
And "b" =
b/sin(44.92) = 13.3/sin(110)
b = 13.3*sin(44.92)/ sin(110) ≈ 10
a = 6 b = 10 c = 13.3
A = 25.08 B = 44.92 C = 110
