+0  
 
0
1367
1
avatar+270 

Let h(t) denote the height of an object in meters at time t seconds. h'(t) is the velocity of the object at time t seconds, and h''(t) = -9.8m/s^2 is the acceleration of the object due to gravity. Suppose that at time t = 0, the height of the object is h(0) = h0 and the velocity of the object is h'(0) = v0. (Here, h0 and v0 are some constants.)

 

A. Find a formula for the velocity function h'(t) in terms of the constant v0.

 

B. Find a formula for the height h(t) in terms of the constants v0 and h0.

 Apr 11, 2016
 #1
avatar+36915 
0

A.  h'(t) = vo   +  t h''(t)   =  vo  - 9.8 t

B. h(t)   = ho  +  vo t + 1/2(-9.8) t^2

 Apr 11, 2016

5 Online Users

avatar
avatar
avatar
avatar