limit of a sequence

\(lim_{x\rightarrow WHERE?}\)

\(\lim_{n\rightarrow \infty} (3+\frac{4}{3}n)=3+\infty=\infty \\~\\ \lim_{n\rightarrow \infty} (3+\frac4{3n})=3+0=3\)

What about this one?

\(\lim_{n\rightarrow \infty}(\frac{\sqrt{2n^3}-1}{n^{\frac32}}) \\~\\ = \lim_{n\rightarrow \infty}(\frac{ \sqrt{2n^3}}{n^{\frac32}}-\frac{1}{n^{\frac32}}) \\~\\ = \lim_{n\rightarrow \infty}( \frac{ 2^{\frac12}n^{\frac32} }{ n^{\frac32}}-\frac{1}{n^{\frac32}}) \\~\\ = \lim_{n\rightarrow \infty}( 2^{\frac12}-\frac{1}{n^{\frac32}} ) \\~\\ =2^{\frac12}-0 \\~\\ =\sqrt2\)