+0

# limits question

0
324
4
+1828

number 20 , how can I do it and there is no function at x = 2

xvxvxv  Oct 21, 2014

#2
+80874
+13

If a function is continuous at "a,"  then, these three conditions have to be met......

Notice that the second and third are met, but not the first one.....as geno has said, this function does not exist at x = 2, so it isn't continuous.......(note that we can see this just from the way the function is defined in the problem itself !!!   x < 2 and x > 2  means that we don't know what happens at 2....)

N

NN

CPhill  Oct 21, 2014
Sort:

#1
+17705
+13

The question is:  Why is it not continuous at x = 2?

You gave the answer to that when you said that it is not defined at that location.

The limit, approaching from both the left and the right is 4; thus, it has a limit at x = 2, even though it is not defined at that location; even though it is not defined at that location. Indeed, there is a 'hole' in the graph at that location, which makes is discontinuous, even though it has a limit at that point.

geno3141  Oct 21, 2014
#2
+80874
+13

If a function is continuous at "a,"  then, these three conditions have to be met......

Notice that the second and third are met, but not the first one.....as geno has said, this function does not exist at x = 2, so it isn't continuous.......(note that we can see this just from the way the function is defined in the problem itself !!!   x < 2 and x > 2  means that we don't know what happens at 2....)

N

NN

CPhill  Oct 21, 2014
#3
+1828
0

thank you geno3141 and CPhill

xvxvxv  Oct 21, 2014
#4
+91434
+10

thanks Chris and Gino,

I really like the way you spelt that out Chris.

Melody  Oct 22, 2014

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