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Limit as x approaches 9 and the equation is (3-rootx)/9-x how do we solve this limit?

Guest Mar 1, 2017
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One way as follows:

 

\(\frac{3-\sqrt x}{9-x}=\frac{3-\sqrt x}{(3-\sqrt x)(3+\sqrt x)}=\frac{1}{3+\sqrt x}\)

 

Hence limit as x tends to 9 is 1/6

.

Alan  Mar 1, 2017

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