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Solve for x

2x-6 = 3(10-2x)/2 + (3+5x)/2

 

I dont get it

 Oct 9, 2017
 #1
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In order to solve for x in this equation, we must perform a multitude of operations.

 

\(2x-6=\frac{3(10-2x)}{2}+\frac{3+5x}{2}\) Multiply by 2 on both sides to eliminate the pesky fractions.
\(4x-12=3(10-2x)+3+5x\) Distribute the 3 into the term 10-2x.
\(4x-12=30-6x+3+5x\) Simplify the right hand side by combining the like terms.
\(4x-12=-x+33\) Add x to both sides to get the x's on one side of the equation.
\(5x-12=33\) Add 12 to both sides.
\(5x=45\) Divide by 5 on both sides of the equation.
\(x=9\)  
   
 Oct 9, 2017

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