+0

# literal equations

+1
54
1
+399

y=mx+b (solve for b)

A=h(b+c) (solve for b)

A=4r^2 (solve for r^2)

7x-y=14 (solve for x)

R= (E/i) (solve for i)

A= (r/2L) (solve for L)

Neptune  Oct 19, 2017

### Best Answer

#1
+5201
+2
 Solve for  b . y   =   mx + b Subtract  mx  from both sides of the equation. y - mx   =   b Solve for  b . A   =   h(b + c) Divide both sides of the equation by  h  . A / h   =   b + c Subtract  c  from both sides of the equation. A / h  -  c   =   b Solve for r2 . A   =   4r2 Divide both sides of the equation by  4 . A / 4   =   r2 Solve for  x . 7x - y  =  14 First add  y  to both sides. See if you can figure the rest out. Solve for  i . R  =  (E / i) Multiply both sides of the equation by  i . i * R  =  E Divide both sides of the equation by  R. i  =  E / R Solve for  L . Using this as the equation  A = $$\frac{r}2$$L , A  =  $$\frac{r}2$$L multiply both sides by  $$\frac2r$$ . $$\frac2r$$ * A  = $$\frac{2}{r}$$ * $$\frac{r}{2}$$ * L $$\frac{2A}{r}$$  =  L If you meant for the equation to be  A = $$\frac{r}{2L}$$ , then it is different!
hectictar  Oct 20, 2017
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### 1+0 Answers

#1
+5201
+2
Best Answer
 Solve for  b . y   =   mx + b Subtract  mx  from both sides of the equation. y - mx   =   b Solve for  b . A   =   h(b + c) Divide both sides of the equation by  h  . A / h   =   b + c Subtract  c  from both sides of the equation. A / h  -  c   =   b Solve for r2 . A   =   4r2 Divide both sides of the equation by  4 . A / 4   =   r2 Solve for  x . 7x - y  =  14 First add  y  to both sides. See if you can figure the rest out. Solve for  i . R  =  (E / i) Multiply both sides of the equation by  i . i * R  =  E Divide both sides of the equation by  R. i  =  E / R Solve for  L . Using this as the equation  A = $$\frac{r}2$$L , A  =  $$\frac{r}2$$L multiply both sides by  $$\frac2r$$ . $$\frac2r$$ * A  = $$\frac{2}{r}$$ * $$\frac{r}{2}$$ * L $$\frac{2A}{r}$$  =  L If you meant for the equation to be  A = $$\frac{r}{2L}$$ , then it is different!
hectictar  Oct 20, 2017

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