So the equation i've got from the question is
4 = 10log10(S1/40)
next I use the rules of logs to rearrange the equation
4 = log10((S1/40)10)
then take the log10 of both sides
0.602 = (S1/40)10
Assuming I have done everything right so far. Where do I take this equation next?
+118608 4 = 10log10(S1/40)
4 = log10((S1/40)10)
Now raise both sides to the power of 10
10^4=10^(log10((S1/40)10)
10000=(S1/40)^10
(10000)^(0.5)=((S1/40)^10)^0.5
100=(S1/40)^5
100*40^5 = S1^5
100*10^5*4^5=S1^5
10 000 000*4^5=S1^5
4*10^(1.4)=S1
S1=100.47 approx
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That was really messy, I will try and check it.
4 = 10log10(S1/40)
0.4=log10(S1/40)
10^0.4=S1/40
40*10^0.4=S1
S1 = 100.47 approx
The second method is much better !!
+118608 4 = 10log10(S1/40)
4 = log10((S1/40)10)
Now raise both sides to the power of 10
10^4=10^(log10((S1/40)10)
10000=(S1/40)^10
(10000)^(0.5)=((S1/40)^10)^0.5
100=(S1/40)^5
100*40^5 = S1^5
100*10^5*4^5=S1^5
10 000 000*4^5=S1^5
4*10^(1.4)=S1
S1=100.47 approx
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That was really messy, I will try and check it.
4 = 10log10(S1/40)
0.4=log10(S1/40)
10^0.4=S1/40
40*10^0.4=S1
S1 = 100.47 approx
The second method is much better !!
