+0  
 
0
181
3
avatar+1222 

Let \(\log_{4}3=x\) . Then \(\log_{2}27=kx\). Find k .

tertre  Apr 14, 2017
Sort: 

3+0 Answers

 #1
avatar+79741 
+2

The first says that     4^x  =  3

 

The second says that  2^(kx)  = 27     

 

Re-writing the first, we have

 

 [ 2^2]^x  = 3

 

[2^x]^2  = 3    cube both sides

 

( [2^x]^2 )^3   = 27

 

2^(6x)  = 27

 

Which implies that  

 

2^(6x)  =   2^(kx)

 

Which implies that  k  = 6

 

 

cool cool cool 

CPhill  Apr 14, 2017
 #3
avatar+5552 
+2

Oh! This makes sense! laughlaughlaugh

I couldn't figure it out earlier! smiley

hectictar  Apr 14, 2017
edited by hectictar  Apr 14, 2017
 #2
avatar+1222 
+1

Thanks!

tertre  Apr 14, 2017

24 Online Users

avatar
avatar
avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details