+1667 What you would do is find the multiples of each number first (besides 0). For 600, there is 600, 1200, 1800, 2400, 3000, 3600, 4000, etc.
And for 108: 108, 216, 324, 432, 540, 648, etc.
The lowest number that is included in both sets would be 5,400, therefore that is the LCM.
+1667 What you would do is find the multiples of each number first (besides 0). For 600, there is 600, 1200, 1800, 2400, 3000, 3600, 4000, etc.
And for 108: 108, 216, 324, 432, 540, 648, etc.
The lowest number that is included in both sets would be 5,400, therefore that is the LCM.
+118608 Excellent work anonymous4338 
Here is another way
$${factor}{\left({\mathtt{600}}\right)} = {{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}}$$
$${factor}{\left({\mathtt{108}}\right)} = {{\mathtt{2}}}^{{\mathtt{2}}}{\mathtt{\,\times\,}}{{\mathtt{3}}}^{{\mathtt{3}}}$$
Include all factors but if the factor appears in both only include it once.
so lowest common multiple will be $${{\mathtt{2}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{3}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{5}}}^{{\mathtt{2}}} = {\mathtt{5\,400}}$$
