math error

What kind of calculator are you using.
-8^(1/3) works fine on my calculator.

What is sqrt(-8,3) looks like the input for some computer language,it is not standard maths notation.

Melody:

What kind of calculator are you using.
-8^(1/3) works fine on my calculator.

What is sqrt(-8,3) looks like the input for some computer language,it is not standard maths notation.

I'm using the web2.0calc.com scientific calculator.
Did you tried to input -8^(1/3) and pressed Enter or on = symbol?

The return is:

You are right . It doesn't work on the web2.0calc.
This is a problem with this calculator.
I don't think that you should rely on this calc - it obviously has some problems.
It works fine on my casio calculator and also on my Sharp calculator.


The web2.0calc also gives a value to 5.5! Where there is no such value.
If you put this into my casio or my sharp calculator it gives an error message - which is what it is supposed to do.

In case you are not familiar with the symbol 5! (5 factorial) means 1*2*3*4*5 = 120 but 5.5! means nothing.

CONCLUSION
There are definitely bugs in the programming of the web2.0 calculator.

you can put negative number inside square root.a square root is something the power of 1/2. for example a square root of 4 means, 4^1/2 or you can write it Sqrt (4,2). for - 8^1/3 , you will write it as Sqrt(-8,3)?? No you can not put a negative number inside a Sqrt.There fore it shoud be sqrt (8,3) or you have some mistakes in your calculation process.

you can not put a negative number inside square root.a square root is something the power of 1/2. for example a square root of 4 means, 4^1/2 or you can write it Sqrt (4,2). for - 8^1/3 , you write it as Sqrt(-8,3)?? No you can not put a negative number inside a Sqrt.There fore it shoud be sqrt (8,3) or you have some mistakes in your calculation process.

If you want to come out with a negative sqrt numbers,there is a concept called imaginary numbers. Assume that i = sqrt(-1), then sqrt(-8,3) = sqrt (8(-1),3) = 2*sqrt(-1), since sqrt(8,3) = 2. consequently,
you will have a result 2*i because we assumed i = sqrt(-1) since,if we have i^2 = -1 then we will have i = sqrt(-1).

In my conclusion if you want come out with sqrt(-8,3) the result will be 2 * i that means two times of i (which is unkown number) but definetly there is a number that multiplies 2.

Bye