(4x-3/-x+9) = (-3/-2)
Please solve for x
Also it helps to write it out as fractions
I'm assuming this might be :
(4x-3)/ (-x+9) = (-3/-2)
(4x - 3) / ( -x + 9) = 3/2 multiply both sides by (-x + 9)
(4x - 3) = (3/2)(-x + 9) multiply both sides by 2 to get rid of the fraction
2(4x -3) = 3(-x + 9) simplify
8x - 6 = -3x + 27 subtract 27, 8x from both sides
-33 = -11x divide both sides by -11
3 = x