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math homework

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if you have a 18 foot diameter circular above dround pool that is \$48.43 what is the cost per square foot of this cover?

Guest Mar 18, 2017
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#1
+5931
+2

How many "square feet" are in the pool cover?

radius = 18 feet / 2

area = π * (9 feet)2

area = 81π square feet

So there are 81π square feet in the pool cover.

...

If there are 2 apples in a basket,

and the total cost of the basket is \$6,

how much does each apple cost individually?

\$6 / 2 apples = \$3 per apple

...

If there are 81π square feet in the pool cover,

and the total cost of the pool cover is \$48.43,

how much does each square foot cost?

\$48.43 / (81π) square feet ≈ \$0.19 per square foot *thx EP

hectictar  Mar 19, 2017
edited by hectictar  Mar 19, 2017
edited by hectictar  Mar 19, 2017
#2
+10837
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radius = 9   area = pi x r^2 = 81pi sq ft

\$48.43/ (81 pi)  =  .1903 ~~~ 19 cents per sq ft

ElectricPavlov  Mar 19, 2017

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