+0

# math question

0
119
2

Suppose that a community in Idaho currently has a population of 5,000 and will be growing with a doubling time of 13 years. What will its population be in 20 years?

What will its population be in 50 years?

Guest May 2, 2017
Sort:

#1
0

First, you have to find out the annual average growth:

2^(1/13) =1.054766...... - 1 x 100 =5.4766% This is the average annual growth rate.

1.054766^20 x 5,000 = ~14,524 expected population of the town in 20 years.

1.054766^50 x 5,000 =~71,908  expected population of the town in 50 years.

Guest May 2, 2017
#2
0

You could also do this way:

20/13 =  1.538462...... This is the number of doublings in 20 years

2^1.538462 x 5,000 =14,524 - projected population in 20 years.

50/13 = 3.8461538....   This is the number of doublings in 50 years.

2^3.8461538 x 5,000 =71,908 - projected population in 50 years.

Guest May 2, 2017

### 13 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details