+0

# math question

0
120
1

What would be the answer to 6 over the square root of 5 minus the square root of 2?

Guest Jul 31, 2017
Sort:

#1
+91229
+1

What would be the answer to 6 over the square root of 5 minus the square root of 2?

I think you mean the simplification rather than the answer:)

$$\frac{6}{\sqrt5}-\sqrt 2\\ =\frac{6}{\sqrt5}*\frac{\sqrt5}{\sqrt5}-\sqrt 2\\ =\frac{6\sqrt5}{5}-\frac{5\sqrt 2}{5}\\ =\frac{6\sqrt5-5\sqrt 2}{5}\\$$

OR maybe you meant:

$$\frac{6}{\sqrt5-\sqrt2}\\ =\frac{6}{\sqrt5-\sqrt2}\times \frac{\sqrt5+\sqrt2}{\sqrt5+\sqrt2}\\ =\frac{6(\sqrt5+\sqrt2)}{(\sqrt5-\sqrt2)(\sqrt5+\sqrt2)}\\ =\frac{6(\sqrt5+\sqrt2)}{5-2}\\ =2(\sqrt5+\sqrt2)\\$$

Melody  Jul 31, 2017

### 7 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details