There are 13 female board members and 12 male board members. If a committee of 10 members is randomly chosen, what is the probability that the committee has exactly 5 females? Round your answer to 6 decimal places as needed.
We want choose any 5 of the 13 females and any 5 of the 12 males =
C(13,5) * C(12,5) = 1019304 (1)
And the total committees possible = C(25, 10) = 3268760 (2)
So the probability = (1) / (2) = 1019304 / 3268760 ≈ 0.311832
