math

I'm assuming that the question is asking for the roots of the expression \((9x+1)(x-1)\).

 

Finding the roots simply means to set the expression equal to zero and solve for any variables. Let's do that!
 

\((9x+1)(x-1)=0\)	Set both factors equal to 0 and solve.
\(9x+1=0\) \(x-1=0\)	Move the constant term over the righthand side.
\(9x=-1\) \(x=1\)
\(x=-\frac{1}{9}=-0.\overline{1}\) \(x=1\)

 

Therefore, the roots are the following:
 

\(x_1=-\frac{1}{9}\)

\(x_2=1\)