+0  
 
0
237
1
avatar

∠ACE is formed by two secants intersecting outside of a circle. If minor arc BD = 28°, minor arc AB = 112°, and minor arc DE = 112°, what is the measure of ∠ACE?

Guest May 1, 2017
Sort: 

1+0 Answers

 #1
avatar+79843 
+1

 

Minor arc AE  =

 

360  - BD  - AB  -  DE  =

 

360  - 28 - 112 - 112   = 108”

 

And the measure  of ACE  =  (1/2) [ minor arc AE  -  minor arc BD ]  =

 

(1/2)  [ 108  -  28 ]  =

 

(1/2) [ 80 ]  =

 

40°

 

 

cool cool cool

CPhill  May 1, 2017

6 Online Users

avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details