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Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.  

Hans007  May 7, 2017
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Sulfuric acid is diluted with water to make, in one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31% acid solution. The contents of the two containers are mixed together. The percentage strength of the acid in the mixture is.  

 

Let P  be the unknown % of acid in the final solution.......we have the following set up

 

Amt of 14% solution * .14   + Amt of 31% solution * .31   =  Total amount * P

 

72 * .14   +   64 * .31   =  (72 + 64)* P          simplify

 

10.08   +  19.84    =   136*P

 

29.92   =   136 * P      divide both sides by 136

 

29.92  / 136   =  P    =    22%

 

 

cool cool cool  

CPhill  May 7, 2017

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