4 5/16IN + 7 1/2IN
\(4\frac{5}{6}IN+7\frac{1}{2}IN=\frac{29}{6}IN+\frac{15}{2}IN\)
\(=\frac{29+3\times 15}{6}IN=\frac{74}{6}IN=12\frac{1}{3}IN\)
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