$f(x)=(x^2-2x-63)/(x+9)$.
f(x)=(x^2-2x-63)/(x+9)
\(f(x)=\frac{(x^2-2x-63)}{(x+9)}\\ x\ne-9\\ f(x)=\frac{(x-9)(x+7)}{(x+9)}\\ \text{can't be simplified}\\ \text{Perhaps your question was meant to be}\\~\\ f(x)=\frac{(x^2 \textcolor{red}{\textbf{+}} 2x-63)}{(x+9)}\quad?\\ \)
