\(r(x)\) has domain \(\{-1,0,1,2\}\) and range \(\{0,2,4,6\}\) . \(s(x)\) has domain \{1,2,3,4\} and is defined by s(x)=x+1 . What is the sum of all possible values of \(s(r(x))\)?
r(x) can be 0, 2, 4, and 6.
So the sum of all possible values of s(r(x)) = s(0) + s(2) + s(4) + s(6)
FREEEZE! there is no s(0) or s(6) because the domain of s(x) is {1,2,3,4}, so get rid of those.
s(2) + s(4)
= (2+1) + (4+1)
= 3 + 5
= 8
+4609 
