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The first two terms of a geometric progression are 4 and  –6.  What is the 4th term?   

Guest Jun 2, 2017

Best Answer 

 #2
avatar+79853 
+2

This is a geometric progression

 

The common ratio is   -6/4  = -3/2

 

So....the nth term in the series can be fornd as

 

an =  a1 (r)(n - 1)    where  a1  =   4  and r  = -3/2

 

So......the 4th term is

 

a4  =  4(-3/2)(4 - 1)  =   4(-3/2)3    =  -27/2  =  -13.5

 

 

 

cool cool cool

CPhill  Jun 2, 2017
edited by CPhill  Jun 2, 2017
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 #1
avatar+91238 
0

The first two terms of a geometric progression are 4 and  –6.  What is the 4th term?   

 

a=4 and d=-6-4=-10

 

\(T_n=a+(n-1)d\\ T_4=4+(4-1)*(-10)\\ T_4=4+(3)*(-10)\\ T_4=4+-30\\ T_4=-26\\ \)

Melody  Jun 2, 2017
 #4
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0

Thank You!! <3

Guest Jun 2, 2017
 #2
avatar+79853 
+2
Best Answer

This is a geometric progression

 

The common ratio is   -6/4  = -3/2

 

So....the nth term in the series can be fornd as

 

an =  a1 (r)(n - 1)    where  a1  =   4  and r  = -3/2

 

So......the 4th term is

 

a4  =  4(-3/2)(4 - 1)  =   4(-3/2)3    =  -27/2  =  -13.5

 

 

 

cool cool cool

CPhill  Jun 2, 2017
edited by CPhill  Jun 2, 2017
 #3
avatar
0

Thank You!!! <3

Guest Jun 2, 2017

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