if 32^3x=1/8, what is x
\(\begin{array}{|rcll|} \hline 32^{3x} &=& \frac18 \\ (2^5)^{3x} &=& 2^{-3} \\ 2^{15x} &=& 2^{-3} \\ 15x &=& -3 \\ x &=& -\frac{3}{15} \\ x &=& -\frac{1}{5} \\ \mathbf{x} &\mathbf{=}& \mathbf{-0.2} \\ \hline \end{array}\)
Solve for x over the real numbers: 32^(3 x) = 1/8
Take the logarithm base 32 of both sides: 3 x = -3/5
Divide both sides by 3: Answer: |x = -1/5
