+0

# MATHS

0
81
4
+502

Express in terms of sin $$\theta$$ only:

$$\frac{cos\theta}{sin\theta}$$

Rauhan  Dec 22, 2017
edited by Rauhan  Dec 22, 2017

#3
+5888
+2

$$\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}$$

*edit*

I don't think that this is correct anymore, but I don't know what the correct answer is.

hectictar  Dec 22, 2017
edited by hectictar  Dec 23, 2017
edited by hectictar  Dec 23, 2017
Sort:

#1
0

= +, - [sqrt(1 - sin^2(theta))] / sin(theta)

Guest Dec 22, 2017
#2
+502
+1

can u write this equation in the latex thingy so i can understand more clearly

Rauhan  Dec 22, 2017
#3
+5888
+2

$$\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}$$

*edit*

I don't think that this is correct anymore, but I don't know what the correct answer is.

hectictar  Dec 22, 2017
edited by hectictar  Dec 23, 2017
edited by hectictar  Dec 23, 2017
#4
+502
+1

the correct answer is

$$\frac{1-sin^2\theta}{sin\theta}$$

Rauhan  Dec 24, 2017

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