Matthew goes hiking every 12 days and swimming every 6 days. He did both kinds of exercise today. How many days from now will he go both hiking and swimming again?
+2440 In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.
This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)
This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)
The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.
+2440 In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.
This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)
This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)
The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.
