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Matthew goes hiking every 12 days and swimming every 6 days. He did both kinds of exercise today. How many days from now will he go both hiking and swimming again?

Guest Jul 26, 2017

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 #1
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In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.

 

This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)

 

This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)

 

The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.

TheXSquaredFactor  Jul 26, 2017
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1+0 Answers

 #1
avatar+1221 
+1
Best Answer

In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.

 

This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)

 

This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)

 

The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.

TheXSquaredFactor  Jul 26, 2017

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