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# MATHS!!!!!

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Matthew goes hiking every 12 days and swimming every 6 days. He did both kinds of exercise today. How many days from now will he go both hiking and swimming again?

Guest Jul 26, 2017

#1
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In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.

This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)

This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)

The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.

TheXSquaredFactor  Jul 26, 2017
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#1
+1491
+1

In 12 days, Matthew will go hiking and swimming on the same day based on his current schedule.

This problem requires one to find the lowest common multiple of 2 numbers; in other words, \(lcm(6,12)=?\)

This one might be more obvious than other problems because 12 is a multiple of 6, and 12 is, of course, a multiple of itself. Therefore, \(lcm(6,12)=12\)

The result of \(lcm(6,12)\) is the fewest number of days until Matthew does both kinds of excerises again.

TheXSquaredFactor  Jul 26, 2017

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