moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.
+118608 moll had some 10 cent coins and 50 cent coins in his savings bank . he had more 10 cent coins than 50 cent coins. the total value of the coins was $15.80.what was the total number of coins that moll had.
10T +50F = 1580 T > F
T +5F = 158
One solution would be T=158 and F=0
10(158 - 5a ) +50( b ) =1580
158, 0
153, 1 = 154 coins
148, 2 = 150 coins
143, 3 = 146 coins
138, 4 = 144 coins
133, 5 = 138 coins
128, 6 = 134 coins
123, 7
118, 8
113, 9
108, 10
103, 11
98, 12
93, 13
88, 14
83, 15
78, 16
73, 17
68, 18
63, 19
58, 20
53, 21
48, 22
43, 23
38, 24
33, 25 58 coins
------------------------------------
(154-58)/4 = 96/4 = 24
So there are many answers all of the form
58+4k where k is any integer and \(0\le k \le 24\)
