x * y = - 48 (1)
x + y = 13 → y = 13 - x (2)
Sub (2) into (1)
x ( 13 - x) = -48
13x - x^2 = -48 rearrange as
x^2 - 13x - 48 = 0 factor
(x - 16) ( x + 3) = 0 set each factor to 0 and solve for x
x - 16 = 0 x + 3 = 0
add 16 to both sides subtract 3 from both sides
x = 16 x = -3
Using (2) to find y
y = 13 - 16 = -3 y = 13 - (-3) = 16
So......the two numbers are 16 and -3