my uncle wrote three different letters and addressed three envelopes. then he went outside for a walk. while he was out, his little daughter put a letter into each envelope and sealed it. what is the probability that none of the letters was in the correct envelope?
Hi Rosala,
here all possibilities:
I.
Letter 1 put into envelope 1
Letter 2 put into envelope 2 or Letter 2 put into envelope 3
Letter 3 must be in envelope 3 Letter 3 must be in envelope 2
we have:
1. Letter 1 in envelope 1
Letter 2 in envelope 2
Letter 3 in envelope 3
2. Letter 1 in envelope 1
Letter 2 in envelope 3
Letter 3 in envelope 2
we can change places 3 times. Letter 1 can start in envelope 1 or in envelope 2 or in envelope 3
so we have 2 * 3 = 6
my uncle wrote three different letters and addressed three envelopes. then he went outside for a walk. while he was out, his little daughter put a letter into each envelope and sealed it. what is the probability that none of the letters was in the correct envelope?
$$\small{\text{
\textcolor[rgb]{0,1,0}{okay} \text{ \textcolor[rgb]{1,0,0}{false}
\begin{array}{|l|c|c|c|}
\hline
$n& letter 1 & letter 2 & letter 3 $ \\
\hline
$1& envelope\ \textcolor[rgb]{0,1,0}{1} & envelope\ \textcolor[rgb]{0,1,0}{2} & envelope\ \textcolor[rgb]{0,1,0}{3} $ \\
$2& envelope\ \textcolor[rgb]{0,1,0}{1} & envelope\ \textcolor[rgb]{1,0,0}{3} & envelope\ \textcolor[rgb]{1,0,0}{2} $ \\
$3& envelope\ \textcolor[rgb]{1,0,0}{2} & envelope\ \textcolor[rgb]{1,0,0}{1} & envelope\ \textcolor[rgb]{0,1,0}{3} $ \\
$\textcolor[rgb]{1,0,0}{4}& envelope\ \textcolor[rgb]{1,0,0}{2} & envelope\ \textcolor[rgb]{1,0,0}{3} & envelope\ \textcolor[rgb]{1,0,0}{1} $ \\
$\textcolor[rgb]{1,0,0}{5}& envelope\ \textcolor[rgb]{1,0,0}{3} & envelope\ \textcolor[rgb]{1,0,0}{1} & envelope\ \textcolor[rgb]{1,0,0}{2} $ \\
$6& envelope\ \textcolor[rgb]{1,0,0}{3} & envelope\ \textcolor[rgb]{0,1,0}{2} & envelope\ \textcolor[rgb]{1,0,0}{1} $ \\
\hline
\end{array}
}}$$
The probability that none of the letters was in the correct envelope is $$\frac{2}{6} = \frac{1}{3} = 33.\overline{3}\ \%$$
heureka....i dont understand you answer...i tried solving this but i couldnt.....can u explain your answer to me please!
Hi Rosala,
There are 6 different possibilities to put 3 letters into 3 envelopes. I have numbered serially them with from 1 to 6. Then I have looked which letters agree with which envelopes. There remain 2 possibilities in those all 3 letters in the envelopes are wrong franked. Then the probability is: 2/6
how come 6, it said ' what is the probability that none of the letters was in the correct envelope' , there are 3 letters and 3 envelopes so it should be 9.......im sooo confused Heureka!
Hi Rosala,
for example if Letter 1 is in envelope 1 then you can't put Letter 2 or Letter 3 into envelope 1.
hi heaureka,...so now i understood why not 9 ...but would you mind telling me why6?im just so confused thats why!thanks!
Hi Rosala,
here all possibilities:
I.
Letter 1 put into envelope 1
Letter 2 put into envelope 2 or Letter 2 put into envelope 3
Letter 3 must be in envelope 3 Letter 3 must be in envelope 2
we have:
1. Letter 1 in envelope 1
Letter 2 in envelope 2
Letter 3 in envelope 3
2. Letter 1 in envelope 1
Letter 2 in envelope 3
Letter 3 in envelope 2
we can change places 3 times. Letter 1 can start in envelope 1 or in envelope 2 or in envelope 3
so we have 2 * 3 = 6