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1. 

Sam puts $1.25 into his piggy bank in January 2013. Each month he increases how much he puts in by 4 cents.

 How much money will he put in his piggy bank in April 2016?

A)$157.25

B)$16.85

C)$3.35

D)$2.81                                                                                                                                     2. 

Sarah's yearly salary is based on a geometric sequence. Her yearly salaries for her first three years are $34,000 , $35,020, and $36,070.60

 What will be her yearly salary for her 7th year?

A)$41,140

B)$40,000

C)$40,597.78

D)$41,815.71

Guest Dec 14, 2017
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2+0 Answers

 #1
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1.

 

There are 39 months between January 2013 and April 2016.

39 x 0.04 cents =$1.56 - the increase in his saving by April 2016

$1.56 + $1.25 =$2.81 - Amount he must put in his piggy bank in April 2016.

 

2.

 

$34,000 x 1.03^6 =$40,597.78 - Sarah's expected salary by  7th year.

Or, you could use the nth term formula to find the same thing:

Nth. Term = ​F x R^(N - 1)

7th. term =$34,000 x 1.03^6 =$40,597.78 - Which is the same as above.

Guest Dec 14, 2017
 #2
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2.   Find the common ratio  =

 

35020 / 34000  =   1.03

 

Salary for nth  year   =   34000 (1.03)n-1

 

Salary for the 7th year  =

 

34000(1/03)7-1  =  34000(1.03)6  =  $40597.78

 

 

cool cool cool

CPhill  Dec 14, 2017

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