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The tires on your bicycle have a diameter of 22 inches. How many rotations does each tire make when you travel 800 feet? Round your answer to the nearest whole number.

Guest Feb 16, 2017

#1
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The tires on your bicycle have a diameter of 22 inches.
How many rotations does each tire make when you travel 800 feet?

Let p = perimeter circle
Let d = diameter circle
Let n = number of rotations

perimeter circle:
$$\begin{array}{|rcll|} \hline p &=& d\cdot \pi \quad &| \quad d = 22\ in. \\ p &=& 22\cdot \pi \ in. \\ \hline \end{array}$$

rotations:

$$\begin{array}{|rcll|} \hline n &=& \dfrac{ 800\ feet \cdot \frac{12\ in.}{1\ feet}} {p} \quad &| \quad 1 feet = 12\ inches \\ n &=& \dfrac{800\cdot 12}{22\cdot \pi} \\ n &=& 138.898859426 \text{ rotations } \\ \hline \end{array}$$

heureka  Feb 16, 2017
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#1
+18777
+10

The tires on your bicycle have a diameter of 22 inches.
How many rotations does each tire make when you travel 800 feet?

Let p = perimeter circle
Let d = diameter circle
Let n = number of rotations

perimeter circle:
$$\begin{array}{|rcll|} \hline p &=& d\cdot \pi \quad &| \quad d = 22\ in. \\ p &=& 22\cdot \pi \ in. \\ \hline \end{array}$$

rotations:

$$\begin{array}{|rcll|} \hline n &=& \dfrac{ 800\ feet \cdot \frac{12\ in.}{1\ feet}} {p} \quad &| \quad 1 feet = 12\ inches \\ n &=& \dfrac{800\cdot 12}{22\cdot \pi} \\ n &=& 138.898859426 \text{ rotations } \\ \hline \end{array}$$