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-4(-3x+5)-3x=3(x-4)-6

Guest Mar 6, 2017
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1. Multiply each term in the parenthesis by -4, 3

\(-4(-3x+5)-3x=3(x-4)-6\)

 

2. Calculate the product

Multiplying two negatives equals a positive: (-)*(-)=(+)

Use rules of multiplication to calculate the expression

\(-4\times (-3x)-4\times 5-3x=3x-12-6\)

 

3. Collect the like terms by subtracting their coefficients

Extract the negative sign from the expression

\(12x-20-3x=-3x=3x-12-6\)

 

4. Subtract the numbers

Add the numbers

\((12-3)x-20=3x-(12+6)\)

 

5. Move variable to the left by adding its opposite to both sides

Move constant to the right by adding its opposite to both sides

\(9x-20=3x-18\)

 

6. Eliminate the opposites

\(9x-3x-20+20=3x-3x-18+20\)

 

7. Collect the like terms by subtracting their coefficients

Keep the sign of the number with the larger absolute value and subtract the smaller absolute value from the larger

\(9x-3x=-18+20\)

 

8. Subtract the numbers

\((9-3)x=+(20-18)\)

 

9. Divide both sides of the equation by 6

\(6x=2\)

 

10. Any expression divided by itself equals 1

Write the division as a fraction

\(6x\div 6=2\div 6\)

 

11. Reduce the fraction with 2

\(x={2\over 6}\)

 

Answer

\(x={1\over 3}\)

 

Alternative form

\(x=\approx 0.333333\)

 

 

 

And there goes 30 minutes of my life... 


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