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​ Need some help/clarification with this problem. (Geometry)

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SA w/ Cylinders.

imjkvelasco  Mar 29, 2017
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#1
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Because the two cylinders are similar, you can use a proportion to determine the height of the larger cylinder

$$3/7 = 5/x$$

By solving the proportion, you get a value for x

$$x = 1 \frac23$$

Now, by multiplying the radius of the larger cylinder by the x value we just found, we can find the height of the larger cylinder

$$1 \frac23*7= 11 \frac23$$

Now, just subsitute the newly found height, and width of the cylinder into the surface area equation

$$A = 2 \pi r h + 2 \pi r^2$$

$$A = 2 \pi (5)(11\frac23)+2 \pi(5)^2$$

$$A \approx 523.6$$

The surface area of the larger cylinder is $$\textbf 5 \textbf 2 \textbf 3 \textbf . \textbf 6 \space \textbf m^ \textbf 2$$

austinruffino  Mar 30, 2017
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Thank you so much, I'm starting to understand it now. (Thanks for clarifying and listing steps!)

imjkvelasco  Mar 30, 2017

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