(5x^3)/ (3x^2y) simplifies to (5x) / ( 3y)
So we have
[(5x) / (3y) ] ÷ [ (25)/ (3y^9) ] invert the second fraction and multiply
[ (5x)/ ( 3y) ] * [ (3y^9)/ ( 25) ] swap denominators
[(5x) / (25)] * [ (3y^9) / (3y) ] =
(x / 5) * ( y^8) =
( x * y^8) / 5
