+0  
 
0
201
3
avatar+5150 

 

Tell if these statements are always, sometimes, or never true.

rarinstraw1195  Dec 14, 2016

Best Answer 

 #3
avatar+75977 
+11

59. Let N be rhe number.......so we have

 

N - logb 1  =

 

N - 0  =

 

N       always true

 

 

60.  Never true.....

 

61.  We are using log a^2  =  2 log a  ......always true

 

62. Not generally  true......unless the log itself can be easily calculated......example.....

 

log39 + log28  =

 

2 + 3   =  5

 

 

63.  log6 16 / log6 8

 

Using the change-of-base rule, we have  [log 16/ log 6]/ [log 8/ log6] =

 

[log 16/ log 6]*  [log 6/ log8]  =   log 16/ log 8   =  log8 16  = 4/3

 

 

64. log (log N)= N....I don't believe this is ever true

 

 

 

 

cool cool cool

CPhill  Dec 14, 2016
Sort: 

3+0 Answers

 #1
avatar+90127 
+10

Come on rarinstraw, we are not here to do all your homework for you.    sad

 

Try them with some numbers ans see what happens. 59 looks pretty easy.

63 is easy

 

If you look at the formulary on this site the log rules are there.

Melody  Dec 14, 2016
 #2
avatar+5150 
0

You are correct Melody, I'm being quite lazy. Very sorry sad

rarinstraw1195  Dec 14, 2016
 #3
avatar+75977 
+11
Best Answer

59. Let N be rhe number.......so we have

 

N - logb 1  =

 

N - 0  =

 

N       always true

 

 

60.  Never true.....

 

61.  We are using log a^2  =  2 log a  ......always true

 

62. Not generally  true......unless the log itself can be easily calculated......example.....

 

log39 + log28  =

 

2 + 3   =  5

 

 

63.  log6 16 / log6 8

 

Using the change-of-base rule, we have  [log 16/ log 6]/ [log 8/ log6] =

 

[log 16/ log 6]*  [log 6/ log8]  =   log 16/ log 8   =  log8 16  = 4/3

 

 

64. log (log N)= N....I don't believe this is ever true

 

 

 

 

cool cool cool

CPhill  Dec 14, 2016

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